.1x^2-x+1.5=0

Solution for .1x^2-x+1.5=0 equation:

.1x^2-x+1.5=0

We add all the numbers together, and all the variables

.1x^2-1x+1.5=0

a = .1; b = -1; c = +1.5;
Δ = b2-4ac
Δ = -12-4·.1·1.5
Δ = 0.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{0.4}}{2*.1}=\frac{1-\sqrt{0.4}}{0.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{0.4}}{2*.1}=\frac{1+\sqrt{0.4}}{0.2}
$